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Calculate the half-life of a first order reaction from their rate constants given below: (i) 200 s^(-1)"" (ii) 2"min"^(-1)""(iii) 4"years"^(-1) |
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Answer» Solution :Half-life PERIOD of a first order REACTION is GIVEN by `t_(1//2)=(0.693)/(K)` (i) `t_(1//2)=(0.693)/(200s^(-1))=0.346 xx 10^(-2)s=3.46xx10^(-3)s` (ii) `t_(1//2)=(0.693)/(2"min"^(-1))=0.346` min (iii) `t_(1//2)=(0.693)/(4" year"^(-1))=0.173` year. |
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