1.

Calculate the half-life of a first order reaction from their rate constants given below: (i)200 s^(-1) (ii) 2 "min"^(-1) (iii) 4 "years"^(-1)

Answer»

Solution :For any FIRST order
Reaction `r_((1)/(2))=(0.693)/(k)`
(i)`t_((1)/(2))(200 s)=(0.693)/(200 s)` Where ,k=`200^(-1) s`
`=3.465xx10^(-3)s^(-1)`
(ii)`t_((1)/(2)) (2min )=(0.693)/(2 min )=0.3465 min^(-1)`
(III)`t_((t)/(2))(4 year)=(0.693)/(4year)=0.17325 year`


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