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Calculate the generation time of a bacterial population in which the number of bacteria increase from 104 /ml to 107 /ml during four hours of exponential growth. |
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Answer» u = 2.303(log Xt – log X0)/t u = 2.303(log 107 - log 104)/4 (X0 = 104 , Xt = 107 , t = 4 hours) Solving the above equation by using the values, we get, u = 1.73/hr td = 0.693/1.73 = 0.4 hrs 0.4 x 60 = 24 mins |
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