1.

Calculate the freezing point of solution when 1.9 g of MgCl_(2) (M = "95 g mol"^(-1)) was dissolved in 50 g of water, assuming MgCl_(2) undergoes complete ionization (K_(f)" for water = 1.86 K kg mol"^(-1))

Answer»


Solution :`DeltaT_(f)=iK_(f)m`
`MgCl_(2) RARR MG^(2+)+2Cl^(-),i=3`
`"Molality "=(1.9)/(95)xx(1)/(50)xx1000=0.4`
`DeltaT_(f)=3xx1.86xx0.4=2.232`
`therefore""T_(f)=273-2.232=270.77K`


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