1.

Calculate the freezing point of an aqueous solution containing 10.50 g of MgBr_(2)in 200 g of water (molar mass of MgBr_(2) = 184g. K_(f) for water = 1.86 K kg mol^(-1))

Answer»

Solution :`Delta T_(f) = 7.5^(@)` C
`Delta T_(f) = iK_(f)`m
`T_(f)^(@) = 3 XX 1.86^(@) C kg "mol"^(-1)`
`xx (10.50 G )/(184 "g mol"^(-1)) xx (1000)/(200 kg)`
`0^(@) C - T_(f) = 1.59^(@)` C
`T_(f) = - 1.59^(@) `C or 271.41K


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