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Calculate the freezing point of a containing 60g of glucose (Molar mass=180 g mol^-1) in 250g of water (K_l of water =1.86 K kg mol^-1) |
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Answer» SOLUTION :`DELTA T_f=k_tm` `=k_f (w_2 times 1000)/(M_2 times w_1)` `=(1.86 times 60 times 1000)/(180 times 250)` `=2.48K` `Delta T_f= T_f^@=T_f` `2.48=273.15-T_f` `T_f=270.67K//270.52K//-2.48^@C` |
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