1.

Calculate the freezing point depression expected for 0.0711M aqueoussolution of Na_(2) SO_(4). If this solution actually freezes at -0.320^(@) C , what would be the value of van't Hoff factor ? (K_(f) = 1.86^(@) C mol^(-1))

Answer»

Solution :`DeltaH_(F) = K_(f) xx M`
`DELTA T_(f) = 1.86 xx 0.0711 = 0.132`
OBSERVED FREEZING point = `0 - (-0.320) = 0.320^(@) C`
`i= ("Observed freezing point")/("Calculate freezing point")`
`(0.320)/(0.132) = 2.42`


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