1.

Calculate the freezing point depression expected for 0.0711 m aqueous solution of Na_(2)SO_(4). If this solution actually freezes at -0.320^(@)C, what would be the value of van't Hoff factor ? (K_(f) for water is "1.86 C mol"^(-1)).

Answer»


SOLUTION :EXPECTED (calculated) `DeltaT_(f)=K_(f)xxm=1.86xx0.0711=0.132^(@)C` (assuming no DISSOCIATION)
Actual (OBSERVED )`DeltaT_(f)=0.320^(@)C`
`i=((DeltaT_(f))_("obs"))/((DeltaT_(f))_("cal"))=(0.320)/(0.132)=2.42.`


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