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Calculate the freezing pint of a solution contaning 0.5g KCl ( Molar mass = 74.5g//mol) dissolved in 100 g water , assuming KCl to be 92% ionised . K_(f) of water = 1.86Kkg/mol. |
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Answer» Solution : `KClrightarrowK^(+)+Cl^(-)` n=2 `i=1-alpha+nalpha` `i=1+alpha` APPLYING the reaction `DeltaT_(F)=iK_(f)m` `=(1+0.92)xx1.86xx(0.5xx1000)/(7.4.5xx100)` `DeltaT_(f)= 0.24` `DeltaT_(f)= t_(f)^(o)=T_(f)`or `t_(f)= -0.24@C` |
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