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Calculate the free energy change when 1 mole of NaCl is dissolved in water at 25°C. Lattice energy of NaCl = 777.8 kJ and ΔS for dissolution = 0.043 kJ and hydration energy of NaCl = –774.1 kJ . |
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Answer» when 1mole of NACL dissolved in WATER at 25℃;Lattice energy of NaCl = 777.8 KJ/molHydration energy of NaCl = -774.1 KJ/molWe know that, We know that, Where, |
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