Calculate the force required to move a train of 2000 quintal up on an incline plane of 1 in 50 with an acceleration of 2 ms^(-2). The force of friction per quintal is 0.5 N.

Calculate the force required to move a train of 2000 quintal up on an

1.	Calculate the force required to move a train of 2000 quintal up on an incline plane of 1 in 50 with an acceleration of 2 ms^(-2). The force of friction per quintal is 0.5 N.
Answer» Solution :Force of friction = 0.5 N per QUINTAL `f = 0.5 xx 2000= 1000`per quintal m = 2000 quintals =` 2000 xx 100` kg ` sin theta = 1/50 , a=2m//s^2` In MOVING up an inclined PLANE, force REQUIRED against gravity `= mg sin theta= 39200N` And force required to produce acceleration = ma. ` = 2000 xx 100 xx 2 = 40,0000 N` Total force required = 1000+ 39,200 + 40,0000 = 440200 N.