Calculate the force required to move a train of 2000 quintal up on an incline plane of 1 in 50 with an acceleration of 2"ms"^(-2). The force of friction per quintal is 0.5 N.

Calculate the force required to move a train of 2000 quintal up on an

1.	Calculate the force required to move a train of 2000 quintal up on an incline plane of 1 in 50 with an acceleration of 2"ms"^(-2). The force of friction per quintal is 0.5 N.
Answer» Solution :Force of friction =0.5N per qunital `f=0.5 xx 2000=1000N` `m=2000" QUINTALS"=2000 xx 100 kg` `sin THETA=1/50, a=2m//s^(2)` In MOVING up an inclined plane, force required against GRAVITY `=MG sin theta= 39200N` And force required to produce acceleration `=ma = 2000 xx 100 xx 2= 40,0000 N` Total force required =1000 + 39,200 + 40,0000 `=440200 N.`