Calculate the force required to double the length of a wire of diamete

1.	Calculate the force required to double the length of a wire of diameter 2mm. (Y=1.2xx10^(11)N//m^(2))
Answer» Solution :Strain `=(Deltal)/(l)=(l)/(l)1, :. Deltal=2l-1=l` `Y+("Stress")/("Strain")=(F)/(pir^(2)x1)`, where `tau= 1 mm =10^(-3)m` `rArr F= gamma X pi R^(2)=1.2xx10^(11) XX pi xx10^(-6)` `F=1.2xx pi xx10^(5)N=3.768xx10^(5)N=3.810^(5)N` `:.` Force `=3.8xx10^(5)N`

Discussion