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Calculate the final temperature of a monoatomic idal gas that is compressed reversible and adiabatically from `16L` to `2L` at `300 K :`A. 600 KB. 1044.6 KC. 1200 KD. 2400 K

Answer» Correct Answer - C
`T.V^(gamma-1)` = constant
`therefore" "(T_(2))/(T_(1))=((V_(1))/(V_(2)))^(gamma-1)`
`implies" "T_(2)=300xx((16)/(2))^((5)/(3)-1)`
=1200 K


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