Calculate the extent of hydrolysis of 0.005 M K2CrO4. [K2= 3.1 *10^-7

1.	Calculate the extent of hydrolysis of 0.005 M K2CrO4. [K2= 3.1 *10^-7 for H2CrO4]
Answer» HERE IS YOUR ANSWER CrO4^-2 + HOH ==> HCrO4^- + OH^- Kh = KB = (KW/k2) = (HCrO4^-)(OH^-)/(CrO4^-2) You know (CrO4^-2), Kw, and k2. (HCrO4^-) = (OH^-) = x. Solve for x to determine (HCrO4^-), then extent hydrolysis = (HCrO4^-)/(CrO4^-2). PLEASE MARK BRAINLIEST HOPE IT HELPED BE BRAINLY!!!!!!!!!!!!! THANKS

Calculate the extent of hydrolysis of 0.005 M K2CrO4. [K2= 3.1 *10^-7 for H2CrO4]

Answer»

CrO4^-2 + HOH ==> HCrO4^- + OH^-

Kh = KB = (KW/k2) =

(HCrO4^-)(OH^-)/(CrO4^-2)

You know (CrO4^-2), Kw, and k2. (HCrO4^-) = (OH^-) = x.