1.

Calculate the extent of hydrolysis and the pH of 0.1 M ammonium acetate Given that K_a=K_b=1.8 times 10^-4

Answer»

SOLUTION :`h=sqrtK_a=SQRT((K_w)/(K_aK_b))=sqrt((1 times10^-14)/(1.8 times10^-5 times1.8 times10^-5))=sqrt(1/1.8 times10^-4)=sqrt(0.5555 times10^-4)`
`=0.7453 times 10^-2`
`pH=1/2 pK_w+1/2 pK_a-1/2 pK_b`
Given that `K_a=K_b=1.8 times 10^-5`
if `K_a=K_b`, if then `pK_a=pK_b`
`therefore pH=1/2 pK_w=1/2(14)=7`


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