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| 1. |
Calculate the equivalent weight of K_(4) [Fe(CN)_(6)] for the following reaction K_(4) [Fe(CN)_(6)] rarr K^(o+) + Fe^(3+) + CO_(2) + NO_(3)^(-) (M = M. Wt. of K_(4) [Fe( CN)_(6) ]) |
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Answer» `M//1` |
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