1.

Calculate the equivalent weight of K_(4) [Fe(CN)_(6)] for the following reaction K_(4) [Fe(CN)_(6)] rarr K^(o+) + Fe^(3+) + CO_(2) + NO_(3)^(-) (M = M. Wt. of K_(4) [Fe( CN)_(6) ])

Answer»

`M//1`
`M//13`
`M//61`
`M//48`

ANSWER :C


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