Calculate the equilibrium constant of the reaction:Fe+2(aq)+Ag+(aq)→ – InterviewSolution

1.	Calculate the equilibrium constant of the reaction:Fe+2(aq)+Ag+(aq)→Fe+3(aq)+Ag(s)Given : E∘Ag+/Ag=0.8 VE∘Fe+3/Fe+2=0.77 V2.303RTF=0.06 V√10=3.16
Answer» Calculate the equilibrium constant of the reaction: $F e_{(a q)}^{+ 2} + A g_{(a q)}^{+} \to F e_{(a q)}^{+ 3} + A g_{(s)}$ Given : $E_{A g^{+} / A g}^{\circ} = 0.8 V E_{F e^{+ 3} / F e^{+ 2}}^{\circ} = 0.77 V \frac{2.303 R T}{F} = 0.06 V \sqrt{10} = 3.16$

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