1.

Calculate the equilibrium constant K_(sp) for the reaction AgCl(s) hArr Ag^(+)(aq)+Cl^(-)(aq) Using the data : DeltaG_(f)^(0)(AgCl)=-109.7 kJ, DeltaG_(f)^(0)(Ag^(+))=77.1 kJ and DeltaG_(f)^(0)(Cl^(-))=-131.2 kJ.

Answer»

SOLUTION :`DELTAG^(@)` for the reaction is calculated as
`DeltaG^(@)=77.1+(-131.2)-(-109.7)=55.6kJ`
We have,
`DeltaG^(@)=-2.303RTlogK`
`logK=(DeltaG^(@))/(2.303RT)=(55.6xx10^(3))/(2.303xx8.314xx298)=-9.75`
`:.K=K_(SP)=1.8xx10^(-10)`


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