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Calculate the equilibrium constant for the reaction given E_("cell")^(@) = +0.46 V Cu(s) + 2Ag^(+) (aq) |
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Answer» Solution :We know `K = "Antilog" [NE^(@)]/[0.059]` =Antilog `[(2 xx 0.46)/(0.059)] = 3.92 xx 10^(15)` |
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