1.

Calculate the equilibrium constant for the reaction, 2Fe^(3+)+3^(-)hArr2Fe^(2+)+I_(3)^(-). The standard reduction potentials in acidic condtitions are 0.77 and 0.54 V respectively for Fe^(3+)//Fe^(2+) and I_(3)^(-)//I^(-) couples.

Answer»


SOLUTION :CELL is `I^(-)|I_(3)^(-)||Fe^(3+)|Fe^(2+),E_(cell)^(@)=0.77-0.54=0.23V,n=2`


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