Calculate the entropy change accompanying the following change of stat

1.	Calculate the entropy change accompanying the following change of state.H2O(s,−10∘C,1atm) → H2O(l,10∘C,1atm)CP for ice = 9 cal deg−1mol−1CP for H2O = 18 cal deg−1 mol−1Latent heat of fusion of ice = 1440 cal mol−1 at 0∘C
Answer» Calculate the entropy change accompanying the following change of state. $H_{2} O (s, - 10^{\circ} C, 1 a t m) \to H_{2} O (l, 10^{\circ} C, 1 a t m)$ $C_{P}$ for ice = $9 c a l d e g^{- 1} m o l^{- 1}$ $C_{P}$ for $H_{2} O$ = $18 c a l d e g^{- 1} m o l^{- 1}$ Latent heat of fusion of ice = $1440 c a l m o l^{- 1}$ at $0^{\circ} C$

Calculate the entropy change accompanying the following change of state.H2O(s,−10∘C,1atm) → H2O(l,10∘C,1atm)CP for ice = 9 cal deg−1mol−1CP for H2O = 18 cal deg−1 mol−1Latent heat of fusion of ice = 1440 cal mol−1 at 0∘C

Answer»

Calculate the entropy change accompanying the following change of state.

$H_{2} O (s, - 10^{\circ} C, 1 a t m) \to H_{2} O (l, 10^{\circ} C, 1 a t m)$

$C_{P}$ for ice = $9 c a l d e g^{- 1} m o l^{- 1}$

$C_{P}$ for $H_{2} O$ = $18 c a l d e g^{- 1} m o l^{- 1}$

Latent heat of fusion of ice = $1440 c a l m o l^{- 1}$ at $0^{\circ} C$