1.

Calculate the enthalpy of vaporisation of I_(2) if the sublimation energy and enthalpy of fusion of I_(2) is 57.3 kJ mol^(-1) and 15.5 kJ mol^(-1) respectively

Answer»

`-72.8" KJ "mol^(-1)`
`72.8" kJ "mol^(-1)`
`-41.8" kJ "mol^(-1)`
`+41.8" kJ "mol^(-1)`

Solution :(i) `I_(2)(s) to I_(2)(g),DeltaH_(1)=+57.3" kJ "mol^(-1)`
(ii) `I_(2)(s) to I_(2)(l),DeltaH_(2)=+15.5" kJ "mol^(-1)`
(III) `I_(2)(l)toI_(2)(g),DeltaH=?`
EQUATION (iii) can be achieved by =(i)-(ii)
`DeltaH=57.3-15.5=+41.8kJ" "mol^(-1)`


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