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Calculate the enthalpy of formation of acetic acid from the following data. CH_3COOH(I) +202 (g) — 2C02 (g) +2H20(I),"" Delta H= -207.9 kcal C(s) +O_2 (g) —C0_2 (g) . ..(ii)Delta H= -94.48 kcal H_(2)(g)+(1)/(2)O_(2)(g)to H_(2)O(l),""Delta H =-68.4k cal |
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Answer» Solution :The REQUIRED equation is , `2C(s)+2H_(2)(G)+O_(2)(g)to CH_(3)COOH(l), "" Delta H=?` This equation can be obtained by multiplying equation (ii) by 2 and also equation (iii) by 2 and ADDING both and finallysubtracting equation (i). `2C(s)+2O_(2)(g)+2H_(2)(g)+O_(2)(g)-CH_(3)COOH(l)-2O_(2)(g)to 2CO_(2)(g)+2H_(2)O(l)-2CO_(2)(g)-2H_(2)O(l)` `2C(s)+2H_(2)(g)+O_(2)(g)to CH_(3)COOH(l)` `Delta_(f)H[CH_(3)COOH(l)=2xx(-94.48)+2xx(-68.4)-(-207.9)` `=-188.96-136.8+207.9` `=-325.76=-117.86` K cal. |
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