Calculate the enthalpy of combustion of benzene (l) on the basis of the following data: (i) Resonance energy of benzene (l) = -152 kJ/mol. (ii) Enthalpy of hydrogenation of cyclohexene (l) = -119 kJ/mol. (iii) DeltaH_(l)^(@) of H_(2)O (l) = -285.8 kJ/mol. (iv) DeltaH_(l)^(@) of H_(2)O (l) = -285.8 kJ/mol (v) DeltaH_(l)^(@) of CO_(2)(g) = -393.5 kJ/mol.

Calculate the enthalpy of combustion of benzene (l) on the basis of th

1.	Calculate the enthalpy of combustion of benzene (l) on the basis of the following data: (i) Resonance energy of benzene (l) = -152 kJ/mol. (ii) Enthalpy of hydrogenation of cyclohexene (l) = -119 kJ/mol. (iii) DeltaH_(l)^(@) of H_(2)O (l) = -285.8 kJ/mol. (iv) DeltaH_(l)^(@) of H_(2)O (l) = -285.8 kJ/mol (v) DeltaH_(l)^(@) of CO_(2)(g) = -393.5 kJ/mol.
Answer» SOLUTION : `DeltaH_(1)^(@)` (benzene) =-156 + 357 = 201 kJ/mol. RESONANCE energy `=DeltaH_(L)^(@) - DeltaH_(l)^(@)` `DeltaH_(l)`(benzene) = -152 + 201 = 49 kJ/mol. Actual + `15/2 O_(2)(l) to 6CO_(2)(G) + 3H_(2)O(l)`. `DeltaH^(@) = 6DeltaH_(l)^(@) CO_(2)(g) + 3DeltaH_(l)^(@)H_(2)O(l) - DeltaH_(l)^(@)` (benzene) `=6(-393.5) + 3(-285.8)-49` `=-3267.4` kJ/mol.