Calculate the enthalpy change for the reaction H2 (g) + Br2 (g) 2HBr (

1.	Calculate the enthalpy change for the reaction H2 (g) + Br2 (g) 2HBr (g) Given that the bond enthalpies of H–H, Br–Br, H–Br are 435, 192 and 364 kJ mol–1 respectively.
Answer» Δ_r H = ∑B.E. (Reactants) – ∑B.E. (Products) = [B.E. (H₂) + B.E. (Br₂ )] – 2 B.E. (HBr) = 435 + 192 – 2 × 364 = – 101 kJ.

Calculate the enthalpy change for the reaction H2 (g) + Br2 (g) 2HBr (g) Given that the bond enthalpies of H–H, Br–Br, H–Br are 435, 192 and 364 kJ mol–1 respectively.

Answer»

Δ_r H = ∑B.E. (Reactants) – ∑B.E. (Products)

= [B.E. (H₂) + B.E. (Br₂ )] – 2 B.E. (HBr)

= 435 + 192 – 2 × 364 = – 101 kJ.

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Calculate the enthalpy change for the reaction H2 (g) + Br2 (g) 2HBr (g) Given that the bond enthalpies of H–H, Br–Br, H–Br are 435, 192 and 364 kJ mol–1 respectively.

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