Calculate the enthalpy change for the processCCl4(g) → C(g) + 4Cl(g)

1.	Calculate the enthalpy change for the processCCl4(g) → C(g) + 4Cl(g)and calculate bond enthalpy of C–Cl in CCl4(g).ΔvapHθ (CCl4) = 30.5 kJ mol–1.ΔfHθ (CCl4) = –135.5 kJ mol–1.ΔaHθ (C) = 715.0 kJ mol–1, where ΔaHθ is enthalpy of atomisationΔaHθ (Cl2) = 242 kJ mol–1
Answer» Calculate the enthalpy change for the process CCl₄₍_g₎ → C₍_g₎ + 4Cl₍_g₎ and calculate bond enthalpy of C–Cl in CCl₄₍_g_). Δ_vapH^θ (CCl₄) = 30.5 kJ mol^–1. Δ_fH^θ (CCl₄) = –135.5 kJ mol^–1. Δ_aH^θ (C) = 715.0 kJ mol^–1, where Δ_aH^θ is enthalpy of atomisation Δ_aH^θ (Cl₂) = 242 kJ mol^–1

Calculate the enthalpy change for the processCCl4(g) → C(g) + 4Cl(g)and calculate bond enthalpy of C–Cl in CCl4(g).ΔvapHθ (CCl4) = 30.5 kJ mol–1.ΔfHθ (CCl4) = –135.5 kJ mol–1.ΔaHθ (C) = 715.0 kJ mol–1, where ΔaHθ is enthalpy of atomisationΔaHθ (Cl2) = 242 kJ mol–1

Answer»

Calculate the enthalpy change for the process

CCl₄₍_g₎ → C₍_g₎ + 4Cl₍_g₎

and calculate bond enthalpy of C–Cl in CCl₄₍_g_).

Δ_vapH^θ (CCl₄) = 30.5 kJ mol^–1.

Δ_fH^θ (CCl₄) = –135.5 kJ mol^–1.

Δ_aH^θ (C) = 715.0 kJ mol^–1, where Δ_aH^θ is enthalpy of atomisation

Δ_aH^θ (Cl₂) = 242 kJ mol^–1