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Calculate the energy released in the fission process. 92U235 + 0n = 56Ba141 + 36Kr92 + 3 0n1. Given M(U235) = 235.0439amu. M(Ba141) = 140.9129,M(Kr92) = 91.8973amu M(0n1) =1.0087amu |
| Answer» Calculate the energy released in the fission process. 92U235 + 0n = 56Ba141 + 36Kr92 + 3 0n1. Given M(U235) = 235.0439amu. M(Ba141) = 140.9129,M(Kr92) = 91.8973amu M(0n1) =1.0087amu | |