1.

Calculate the energy of an electron in the first Bohr orbit of hydrogen.

Answer»

SOLUTION :For hydrogen, Z=1, n=1, we have,
`E_(1)= - (2pi^(2) e^(4)m)/(H^(2))` ….(EQN 2)
`=-(2 xx (3.14)^(2) xx (4.8xx 10^(-10))^(4) xx (9 xx 10^(-28)))/((6.63 xx 10^(-27))^(2))`
`= -2.18 xx 10^(-11)` erg


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