1.

Calculate the empirical formula of gold chloride which contains 35.1% of chlorine. At mass of Au = 197.

Answer»


Solution :`{:("CONSTITUENT",%"age","Mol. MASS","Moles of CONST."=(%)/("Mol. mass"),"SIMPLEST Ratio"),(CaO,48.0,56,48.0//56=0.857,9),(P_(2)O_(5),41.3,142,41.3//142=0.291,3),(CaCl_(2),10.7,111,10.7//111=0.096,1):}`
`therefore"Empirical Formula"=9CaO.3P_(2)O_(5).CaCl_(2).`


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