1.

Calculate the EMF of the following concentration cell at 298K Zn|ZnSO_(4)(0.05M)||ZnSO_(4)(0.5M)|Zn

Answer»

SOLUTION :`E_(Cell)=(0.0591)/(n)"LOG"(C_(2))/(C_(1))=(0.0591)/(2)"log"(0.5)/(0.05)=0.02955V`


Discussion

No Comment Found