1.

Calculate the emf of the following cell at 298K Fe_((s))|Fe^(2+)(0.001M)||H^(+)(1M)|H_(2(g))(1" bar"),Pt_((s)) (Given E_(cell)^(@)=+0.44V)

Answer»


SOLUTION :`Fe+2H^(+)TOFE^(2+)+H_(2)`,
`E_(cell)=E_(cell)^(@)-(0.0591)/(2)"log"([Fe^(2+)])/([H^(+)]^(2))=0.44-(0.0591)/(2)"log"(0.001)/((1)^(2))`


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