Calculate the emf of the concentration cell at 298 K.Pt(s)|H2(g, p1)|H – InterviewSolution

1.	Calculate the emf of the concentration cell at 298 K.Pt(s)\|H2(g, p1)\|HCl(aq)\|H2(g, p2)\|Pt(s)p1=600 torrp2=400 torrTake:log 32=0.176
Answer» Calculate the emf of the concentration cell at $298 K$ . $P t (s) \| H_{2} (g, p_{1}) \| H C l (a q) \| H_{2} (g, p_{2}) \| P t (s)$ $p_{1} = 600 t o r r p_{2} = 400 t o r r$ Take: $l o g \frac{3}{2} = 0.176$

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