1.

Calculate the emf of the cellPt, H2(1.0atm) | CH3COOH (0.1M) || NH3(aq, 0.001M) | H2(1.0 atm), Pt Ka(CH3COOH) = 10−5, Kb(NH3) = 10−5

Answer»

Calculate the emf of the cell


Pt, H2(1.0atm) | CH3COOH (0.1M) || NH3(aq, 0.001M) | H2(1.0 atm), Pt Ka(CH3COOH) = 105, Kb(NH3) = 105





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