1.

Calculate the emf of the cell Zn//ZnO_(2), OH^(-)""_(aq),-HgO""//Hg given that E^(@) values of OH^(-), ZnO and OH^(-), HgO""//Hg half cells are -1.216 V and 0.098 V respectively.

Answer»

SOLUTION :Given :
`Zn//ZnO_(2)^(-), OH^(-)""_((aq)), HgO""//Hg`
`""E^(@)""_(R)=0.098V, E_(L)=-1.216V`
Formula : `therefore E^(@)""_(CELL)=E^(@)""_(R)-E^(@)""_(L)`
Solution : `E^(@)""_(cell)=0.098-(-1.216)`
`""=0.098+1.216=+1.314`
`E^(@)=+1.314V`.


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