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Calculate the emf of the cell : Mg|Mg^(2+)(0.1 M)||Ag^(+)(1.0xx10^(-3) M)|Ag Given that E_(cell)^(@)=3.15" V". |
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Answer» SOLUTION :`E_(cell)^(@)=E_(cell)^(@)-(0.0591)/(n)"LOG"([MG^(2+)])/([Ag^(+)]^(2))` `=3.15-(0.0591)/(2)"log"(0.1)/((1.0xx10^(-3))^(2))` `=3.15-0.02955" log "5` `=3.15-0.02955xx0.6989` `=3.15-0.0207=3.13~~3.0` |
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