Calculate the emf of the cell in mV (atleast first two digits must match with correct answer) Ag(s),AgIO_(3)(s)|Ag^(+)(xM),HIO_(3)(1M)||Zn^(+2)(1M)|Zn(s) if K_(sp)=3xx10^(-8) for AgIO_(3) and K_(a)=(1)/(6) for HIO_(3) and E_(cell)^(0) for 2Ag+Zn^(+2)to2Ag^(+)+Zn is -1.56V. log3=0.48)Take(PT)/(F)=0.059) (giving your answer in magnitude only)

Calculate the emf of the cell in mV (atleast first two digits must mat

1.	Calculate the emf of the cell in mV (atleast first two digits must match with correct answer) Ag(s),AgIO_(3)(s)\|Ag^(+)(xM),HIO_(3)(1M)\|\|Zn^(+2)(1M)\|Zn(s) if K_(sp)=3xx10^(-8) for AgIO_(3) and K_(a)=(1)/(6) for HIO_(3) and E_(cell)^(0) for 2Ag+Zn^(+2)to2Ag^(+)+Zn is -1.56V. log3=0.48)Take(PT)/(F)=0.059) (giving your answer in magnitude only)
Answer» Solution :`K_(a)=(Calphal^(2))/(1-ALPHA)implies(1)/(6)=(alpha^(2))/(1-alpha)impliesalpha=(-1+-sqrt((1)^(2)+4xx6xx1))/(12)=(-1+-sqrt(1+24))/(12)=(1)/(3)` `therefore[IO_(3)^(-)]=1xx(1)/(3)=(1)/(3)Mimplies[Ag^(+)]=(3xx10^(-8))/((1)/(3))=9xx10^(-8)M` Now `2Ag+Zn^(+2)overset(2e^(-))to2Ag^(+)+Zn` gives `E=-1.56+(0.059)/(2)LOG((1)/(9xx10^(-8))^(2))=-1.144V=-1144mV`