1.

Calculate the emf of the cell having the cell reaction 2Ag^(+)+ZnhArr 2Ag+Zn^(2+) and E_("cell")^(@)=1.56V" at "25^(@)C when concentration of Zn^(2+)=0.1M and Ag^(+)=10M in the solution.

Answer»


Solution :HINT : `E_("CELL")=E_("cell")^(@)-(RT)/(NF)ln""([Zn^(2+)])/([AG^(+)]^(2))`


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