Saved Bookmarks
| 1. |
Calculate the emf of given cell {:(Ag|AgNO_(3)||AgNO_(3)|Ag,,E_(Ag^(+)//Ag)=0.80V),(0.001 M, 0.1 M):} |
|
Answer» Solution :The GIVEN cell is concentrated cell. Hence, `E_("cell")^(@)=0` `E_("cell") = E_("cell")^(@) - 0.0591/n log [("PRODUCT")]/[("Reactant")]` `E_("cell") = 0-(0.0591)/1 log 10^(-3)/10^(-1) = 0.118` volt |
|