Calculate the electron affinity of oxygen atom in gaining two electrons to give the oxide ion O−2 from the following data. Standard heat of formation of MgO(s)=−600 kJmol−1 Lattice energy of MgO(s)=−3860 kJmol−1 lonization energy of Mg(g) to give Mg+2 is +2170 kJmol−1 Dissociation energy of O2(g) is +494 kJmol−1 Heat of sublimation of Mg(s) is +150 kJmol−1

Calculate the electron affinity of oxygen atom in gaining two electron

1.	Calculate the electron affinity of oxygen atom in gaining two electrons to give the oxide ion O−2 from the following data. Standard heat of formation of MgO(s)=−600 kJmol−1 Lattice energy of MgO(s)=−3860 kJmol−1 lonization energy of Mg(g) to give Mg+2 is +2170 kJmol−1 Dissociation energy of O2(g) is +494 kJmol−1 Heat of sublimation of Mg(s) is +150 kJmol−1
Answer» Calculate the electron affinity of oxygen atom in gaining two electrons to give the oxide ion $O^{- 2}$ from the following data. Standard heat of formation of $M g O_{(s)} = - 600 k J m o l^{- 1}$ Lattice energy of $M g O_{(s)} = - 3860 k J m o l^{- 1}$ lonization energy of $M g_{(g)}$ to give $M g^{+ 2}$ is +2170 $k J m o l^{- 1}$ Dissociation energy of $O_{2 (g)}$ is +494 $k J m o l^{- 1}$ Heat of sublimation of $M g_{(s)}$ is +150 $k J m o l^{- 1}$