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Calculate the electrode potential of a copper wire dipped in 0.1 M CuSO_(4) solution at 25^(@)C. The standard electrode potential of copper is 0.34 volt. |
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Answer» Solution :The electrode reaction WRITTEN as REDUCTION reaction is `CU^(2+) +2e^(-)toCu` so that n=2 Applying NERNST eqn. we get `E=E^(@)-(0.0591)/(2)"log"(1)/([Cu^(2+)])` `=0.34-(0.0591)/(2)"log"(1)/(0.1)=0.34-0.02955=0.31045`volt. |
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