Calculate the electrode potential developed when a silver electrode in – InterviewSolution

1.	Calculate the electrode potential developed when a silver electrode in dipped in 0.025 M silver nitrate solution at 289K.
Answer» SOLUTION :`E=E^@+0.0591/N LOG [M^(+n)]` `E=+0.8+0.0591/1 log (0.025)` `E=+0.8+0.0591/1 log 2.5 TIMES 10^-2` `E=+0.70531 V`

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