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Calculate the electrode potential at a copper electrode dipped in a 0.1 M solution of copper sulphate at `25^(@)C`. The standard electrode potential of `Cu^(2+)//Cu` system is 0.34 volt at 298 K. |
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Answer» We know that, `E_("red")=E_("red")^(@)+0.0591/n log_(10) ["ion"]` Putting the value of `E_("red")^(@)=0.34 V, n=2` and `[Cu^(2+)]=0.1 M` `E_("red")=0.34+0.0591/2 log_(10) [0.1]` `=0.34+0.02955xx(-1)` `=0.34-0.02955=0.31045` volt |
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