Calculate the electrode potential at 25∘ C of Cr+3,Cr2O2−7 electro – InterviewSolution

1.	Calculate the electrode potential at 25∘ C of Cr+3,Cr2O2−7 electrode at pOH=11 in a solution of 0.01 M both in Cr3+ and Cr2O2−7.Cr2O2−7+14H++6e−→2Cr3++7H2OE∘=1.33 V
Answer» Calculate the electrode potential at $25^{\circ} C$ of $C r^{+ 3}, C r_{2} O_{7}^{2 -}$ electrode at $p O H = 11$ in a solution of $0.01 M$ both in $C r^{3 +}$ and $C r_{2} O_{7}^{2 -}$ . $C r_{2} O_{7}^{2 -} + 14 H^{+} + 6 e^{-} \to 2 C r^{3 +} + 7 H_{2} O$ $E^{\circ} = 1.33 V$

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