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Calculate the efficiency of an engine whose working substance absorbs 3000 J of heat from the source and rejects 2000 J of heat to the sink. |
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Answer» Solution :Heat ABSORBED from the SOURE `= Q_(1) = 3000 J` Heat rejected to the SINK` = Q_(2) = 2000 J` Efficiency `= ETA ( Q_(1) - Q_(2))/( Q_(2))= ( 3000 - 2000)/( 2000) = 0.5 = 50%` |
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