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Calculate the `EAN` of the central metal in the following complex (a) `[AuCI_(2)]^(Θ)` ,(b) `[AI(C_(2)O_(4))_(3)]^(3-)`,(c ) `[(CdI)_(4))]^(Θ)` . |
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Answer» Oxidation state of Au in `[AuCI_(2)]^(Θ)` is `x + 1 (-1) xx 2 = - 1)` `implies x = +1` EAN of Au in `[AuCI_(2)]^(Θ)` is Atomic number of Au - Oxidation state of Au + number of electrons gained by donation from ligands `=79 -1 + 4 =82` For EAN rule total electrons in the above compound should be 86 next noble gas `Rn(Z = 86)` Hence EAN rule in the above copounds is not valid (b) Oxidation state of Al in `[A1(C_(2)O_(4))_(3)]^(3-)` is `x + (-2) xx 3 = -3` ` x = +3` EAN of A1 in `[A1(C_(2)O_(4))_(3)]^(3-)` Atomic number of A1 - Oxidation state of A1 number of electrons gained by donation from ligands Note (en) is bidentate ligand and `C_(2)O_(4)^(2-)` is identate ligand EAN of A1 in `[A1(C_(2)O_(4))_(3)]^(3-)` `=13 -3 + 2(3 xx 2) = 22` For EAN rule total electrons should be 36 next noble gas `Kr(Z=36)` So EAN rule is not valid in the above compounds `[(CdI)_(4)]^(Θ)` Oxidation state of Cd in `[(CdI)_(4)]^(Θ)` is ` x + (-1) x 4 = - 1` ` x + = +3` EAN of Cd in `[(CdI)_(4)]^(Θ)` =Atomic number - Oxidation state of Cd+ number of electrons gained by donation from ligands `= 48 -3+8=53` For EAN rule total electrons should be 54 next noble gas Xe with `(Z =54)` So EAN rule is not valid in the above compound . |
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