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Calculate the drift speed of electron in a copper wire carrying a current of 1A and cross sectional area A = 10^-6 m^2. The electron density of copper that was found experimentally is n = 8.5x10^28 m^–3. (Take q = 1.6X10^-19 C) |
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Answer» Given: a copper wire of cross-sectional area 2.5×10 −7 m 2 carrying a current of 2.7A. The density of conduction electrons to be 9×10 28 m −3 To FIND the AVERAGE drift SPEED of conduction electronsSolution: We know that drift velocity, V d = nq×AI , where I=2.7A is the current, n=9×10 28 m −3 is the CHARGE density, q=1.6×10 −19 is charge electron and A=2.5×10 −7 m 2 is cross-sectional areaThat is, V d = 9×10 28 ×1.6×10 −19 ×2.5×10 −7 2.7 ⟹V d = 14.4×10 9 ×2.5×10 −7 2.7 ⟹V d =0.075×10 −2 ⟹V d =7.5×10 −4 m/sis the required averagedrift velocity of conduction electrons. |
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