1.

Calculate the density of unit cell of sodium, if the edge length of cubic structure is 4.24 angstroms.

Answer»

Solution :`n=` Number of atoms PER unit cell= 2 (SINCE Na CRYSTALLISE in bee lattice)
`M=` Gram atomic mass of sodium `= 23 g mol^(-1)`
`N_(0) =` Avogadro number `=6.023 xx 10^(23) `
`a=` Edge length `=4.24` angstroms `=4.24 xx 10^(-10)m`
Density, `d= (n xx M)/( a^(3) N_(0) ) = ( 2 (23 xx 10^(-3)) )/( 6.023 xx 10^(23) xx (4.24 xx 10^(-10) )^(3) ) = 1.002 xx 10^(3) kgm^(-3)`


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