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Calculate the density of H_(2)SO_(4) solution if its molality and molarity are 94.5 and 11.5 respectively. |
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Answer» SOLUTION :Molarity 11.5 means 11.5 moles of `H_(2)SO_(4)` are present in 1 L of the solution. Suppose the DENSITY of the solution is `"d g mL"^(-1)`, then 1 L, i.e., 1000 mL of solution has mass = 1000 d g THUS, 1000 d g of the solution contain `H_(2)SO_(4)=11.5` moles `=11.5xx98g=1127g` `therefore"Mass of water"=(1000d-1127)g` `"Molality "=(11.5)/(1000d-1127)xx1000=94.5` `"or"11500=94.5xx1000d-94.5xx1127"or"94500d=11500+106501.5=118001.5` `therefore""d=(118001.5)/(94500)=1.2487"g L"^(-1)` |
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