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Calculate the `DeltaG^(@)` of the following reaction :- `Fe^(+2)(aq)+Ag^(+)(aq)toFe^(+2)(aq)+Ag(s)` `E_(Ag^(+)//Ag)=0.8V" "E_(Fe^(+3)//Fe^(+2))^(0)=0.77V`A. `-2895 J mol^(-1)`B. `-3845 J mol^(-1)`C. `-1874 J mol^(-1)`D. `-375 J mol^(-1)` |
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Answer» Correct Answer - A `E_(cell)^(0)=0.8-0.77=0.03 V` `DeltaG^(@)=-nFE_(cell)^(@)=-1xx96500xx0.03` `=-2895 J//mol` |
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